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At 18^(@)C, the specific conductance of ...

At `18^(@)C`, the specific conductance of (N/10) KCl solution is `"0.0112 ohm"^(-1)."cm"^(-1)`. When a conductivity cell is filled with that solution, the resistance of the cell stands at 55 ohm. What is the cell constant of the cell?

Text Solution

Verified by Experts

Specific conductance, `kappa=((1)/(R))xx(l)/(A)`
Substituting, `"R = 55 ohm and "kappa ="0.0112 ohm"^(-1)."cm"^(-1)` into above relation gives
`(l)/(A)=kappa xxR=0.0112 xx55="0.616 cm"^(-1)`
Therefore, the cell constant of the cell is `0.616 cm"^(-1)`.
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