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Lambda(m)^(@)(NaCl)-Lambda(m)^(@)(NaNO(3...

`Lambda_(m)^(@)(NaCl)-Lambda_(m)^(@)(NaNO_(3))="3.7 ohm"^(-1)."cm"^(2)."mol"^(-1)`. Find the value of `Lambda_(LiCl)^(@)-Lambda_(LiNO_(3))^(@)`.

Text Solution

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`Lambda_(m)^(@)(LiCl)-Lambda_(m)^(@)(LiNO_(3))`
`=Lambda_(m)^(@)(Li^(+))+Lambda_(m)^(@)(Cl^(-))-[Lambda_(m)^(@)(Li^(+))+Lambda_(m)^(@)(NO_(3)^(-))]`
`=Lambda_(m)^(@)(Cl^(-))-Lambda_(m)^(@)(NO_(3)^(-))`
`=Lambda_(m)^(@)(NaCl)-Lambda_(m)^(@)(NaNO_(3))`
`="3.7 ohm"^(-1)."cm"^(2)."mol"^(-1)`
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