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2.015 of silver is deposited at the cath...

2.015 of silver is deposited at the cathode when a current of 3A is passed for 10 min through a solution of `AgNO_(3)`. Determine the chemical and the electro- chemical equivalent of silver.

Text Solution

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Quantity of electricity `Q=3xx(10xx60)=1800C`.
Using the relatio, `W=ZxxQ`, we have
`Z=(W)/(Q)=(2.015)/(1800)=1.119xx10^(-3)g.C^(-1)`
Thus, the electrochemical equivalent Ag is `1.119xx10^(-3)g.C^(-1)`
The amount of silver deposited at the cathode by 1800 coulomb of electricity = 2.015 g.
`96500C(1F)` of electricity will deposit `(2.015)/(1800)xx96500=108.02"g of Ag."`
As 1 F of electricity causes the liberation of 1g - equiv of a substance at an electrode, the chemical of Ag will be 108.02.
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