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The specific conductance of a "0.20 mol....

The specific conductance of a `"0.20 mol.L"^(-1)` solution of KCl at 300 K is `"0.026S.cm"^(-1)`. Calculate molar conductivity of the solution.

Text Solution

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`Lambda_(m)=Kxx(1000)/(M)="0.026 S.cm"^(-1)xx(100)/("0.20 mol. cm"^(-3))`
`="130 S.cm"^(2)."mol"^(-1)`
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