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Arrange the following solutions in order...

Arrange the following solutions in order of decreasing specific conductance:
(i) 0.01 M NaCl
(ii) 0.05 M NaCl
(iii) 0.1 M NaCl
(iv) 0.5 M NaCl
Resistance of a conductivity cell filled with 0.1 M KCl solution is `"80 ohm"`. The conductivity cell has a cell constant of `"1.0 cm"^(-1)`. Find out the molar conductance of the KCl solution.

Text Solution

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Ist Part : The specific conductance of an electrolyte solution increases with the increases in concentration of the solution. Therefore, ranking the given solutions in sequence `"0.5M NaCl "gt "0.1 M NaCl "gt ".05 M NaCl "gt "0.01 M NaCl"`
2nd part : First we need to know the specific conductance `(kappa)` of the solution. for this we use the relation `kappa =(1)/(R)xx(l)/(A)` Given that cell constant `((l)/(A))="1.0 cm"^(-1)` and `"R = 80 ohm "kappa =(1)/(80)xx"1 ohm"^(-1)."cm"^(-1)="0.0125 ohm"^(-1)."cm"^(-1)`
To calculate molar conductance `(Lambda_(m))` of the solution, we apply the relation. `Lambda_(m)=kappaxx(1000)/(M)`
Therefore, `Lambda_(m)=0.0125xx(1000)/(0.1)"ohm"^(-1)."cm"^(2)."mol"^(-1)`
`="125 ohm"^(-1)."cm"^(2)."mol"^(-1)`
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