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Determine DeltaG^(@) and the value of th...

Determine `DeltaG^(@)` and the value of the equilibrium constant for the following reaction occurring in an electrochemical cell at `25^(@)C`.
`Cu(s)+2Ag^(+)(aq)rarr Cu^(2+)(aq)+2Ag(s)`
Given that, `E_(Cu^(2+)|Cu)^(@)=0.34V and E_(Ag^(+)|Ag)^(@)=0.80V`

Text Solution

Verified by Experts

`E_("cell")^(@)=E_("cathode")^(@)-E_("anode")^(@)=E_(Ag^(+)|Ag)^(@)-E_(Cu^(2+)|Cu)^(@)`
`=0.80V-0.34V=0.46V`
Applying the relation, `DeltaG^(@)=-nFE_("cell")^(@),` we have
`DeltaG^(@)=-2xx96500xx0.46J=-88.78kJ`
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