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(ii) A current of 35 A is passed through...

(ii) A current of 35 A is passed through acidulated water for 5 min 50 s. How many grams of hydrogen will be liberated at the cathode?

Text Solution

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Quantity of electricity `=35xx(5xx60+50)A=12250A`
Cathode reaction: `2H^(+)(aq)+2e rarr H_(2)(g)`
Anode reaction: `H_(2)O(l)rarr 2H^(+)(aq)+(1)/(2)O_(2)(g)+2e`
Hence amount of electricity required to produce
`"1 mol "H_(2)=2xx96500C`
`therefore" 12250 C electricity evolves "=(12250)/(2xx96500)="0.063 mol"`
`="0.126g of "H_(2)" gas "`
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