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In a conductivity cell, the distance bet...

In a conductivity cell, the distance between the two Pt electrodes is 2.0 cm and each electrode has cross - sectional area of `4.0cm^(2)`. When the cell is filled with a 0.4 molar solution of an electrolyte, the reistance of the cell `25Omega`. Calculate the molar conductivity of the solution.

Text Solution

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Specific conductance, `kappa=(1)/(R)xx(l)/(A)`
given, `l = "2.0cm, A = 4.0 cm"^(2), R=25Omega`
`therefore" specific conductance of the soltuion"`
`=(1xx2)/(25xx4)="0.02 ohm"^(-1)."cm"^(-1)`
concentration of the solution `= 0. 4M`
`Lambda_(m)=kappa xx(1000)/(M)=0.02xx(1000)/(0.4)`
`="50 ohm"^(-1)."cm"^(2)."mol"^(-1)`
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