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Arrange K^(+), Zn^(2+), H^(+), Cu^(2+) i...

Arrange `K^(+), Zn^(2+), H^(+), Cu^(2+)` ions in order of their tendency to be liberated at cathode.
`[E_(cu^(2+)|Cu)^(@)=+0.34V, E_(2H^(+)|H_(2))^(@)=0.00V`,
`E_(Zn^(2+)|Zn)^(@)=-0.76V E_(K^(+)|K)^(@)=-2.93V]`

Text Solution

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The order of increasing standard electrode potential of the given ions: `E_(K^(+)|K)^(@)lt E_(Zn^(2+)|Zn)^(@)ltE_(2H^(+)|H_(2))^(@) lt E_(Cu^(2+)|Cu)^(@)`.
Among the given electrodes `K^(+)|K` and `Cu^(2+)|Cu` has the lowest and highest standard reduction potential, respectively. Thus `Cu^(2+)` has the highest tendency to get reduced wheres K has the highest tendency to get oxidised. Thus the order of increasing tendencies to get liberated at cathode is : `K^(+) lt Zn^(2+) lt H^(+) lt Cu^(2+)`.
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