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Calculate Delta(r)G^(@) for the reaction...

Calculate `Delta_(r)G^(@)` for the reaction
`Mg(s)+Cu^(2+)(aq)rarrMg^(2+)(aq)+Cu(s)`
Given : `E_("cell")^(@)=+2.71V, 1F = "96500 C.mol"^(-1)`

Text Solution

Verified by Experts

In the above cell,
`{:("Anode reaction : "Mg(s)rarrMg^(2+)(aq)+2e),("Cathode reaction :"Cu^(2+)(aq)+2erarrCu(s)),(bar("Cell reaction :"Mg(s)+Cu^(2+)(aq)rarrMg^(2+)(aq)+Cu(s)" ")):}`
`therefore" 2mol of electrons are involved in the cell reaction. So, n = 2"`
`therefore" Change in standard free energy, "Delta_(r)G^(@)=-nFE^(@)`
`=-(2xx96500xx2.71)J=-523030J=-52.30kJ`
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