Home
Class 12
CHEMISTRY
The conductivity of 0.001 mol solution o...

The conductivity of 0.001 mol solution of `CH_(3)COOH` is `3.905xx10^(-5)" S.cm"^(-1)`. Calculate its molar conductivity and degree of dissociation `(alpha)`. `["Given: "lambda^(@)(H^(+))="349.6 S.cm"^(2)."mol"^(-1)` and `lambda^(@)(CH_(3)COO^(-))="40.9 S.cm"^(2)."mol"^(-1)]`

Text Solution

Verified by Experts

Molar conductivity,
`Lambda_(m)=kappa xx(1000)/(M)=3.905xx10^(-5)xx(1000)/(0.001)`
`="39.05 S.cm"^(2)."mol"^(-1)`
`Lambda_(m)^(@)(CH_(2)COOH)=lambda^(@)(H^(+))+lambda^(@)(CH_(3)COO^(-))`
`=(349.6+40.9)"S.cm"^(2)."mol"^(-1)="390.5 S.cm"^(2)."mol"^(-1)`
`"Degree of dissociation of "CH_(3)COOH`,
`alpha=(Lambda_(m))/(Lambda_(m)^(@))=(39.05)/(390.5)=0.1`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise SOLVED CBSE SCANNER (DELHI - 2017)|4 Videos

  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise SOLVED CBSE SCANNER (OUTSIDE DELHI - 2017)|4 Videos

  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise SOLVED CBSE SCANNER (DELHI - 2016)|5 Videos

  • D - AND F - BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET 8 (Answer the following questions)|10 Videos

  • ENVIRONMENTAL CHEMISTRY

    CHHAYA PUBLICATION|Exercise PRACTICE SET 14(Answer the following questions)|6 Videos

Similar Questions

Explore conceptually related problems

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S.cm^(-1) . Calculate the molar conductivity of the KCl solution.

Molar conductivity of "0.025 mol.L"^(-1) methanoic acid is "46 S.cm"^(2)."mol"^(-1) . Calculate its degree of dissociation and dissociation constant. Given : lambda^(@)(HCOO^(-))="54.6 S.cm"^(2)."mol"^(-1), lambda^(@)(H^(+))="349.6 S.cm"^(2)."mol"^(-1) .

The specific conductance of a "0.20 mol.L"^(-1) solution of KCl at 300 K is "0.026S.cm"^(-1) . Calculate molar conductivity of the solution.

The specific conductance of a 0.12 N solution of an electrolyte is 2.4xx10^(-2) S Cm^(-1) . Calculate its equivalent conductivity,

Calculate the degree of dissociation (alpha) of acetic acid it its molar conductivity (Lambda_(m)) is "39.05 S.cm"^(2)."mol"^(-1) Given lambda_(H)^(@)="349.6 S.cm"^(2)."mol"^(-1) and lambda_(CH_(3)COO^(-))^(@)="40.9 S.cm"^(2)."mol"^(-1) .

Conductivity of 0.00241M acetic acid solution is 7.896xx10^(-5)S.cm^(-1) . Calculate its molar conductivity. If Lambda_(m)^(@) for acetic acid is 390.5S.cm^(2).mol^(-1) , what is its dissociation constant ?

The conductivity of "0.001028 mol.L"^(-1) acetic acid is 4.95xx10^(-5)"S.cm"^(-1) . Calculate its dissociation constant if Lambda_(m)^(@) for acetic acid is "390.5 S.cm"^(2)."mol"^(-1) .

The molar conductivities of acetic acid at 298K at the molar concentration of 0.1 is 5.20 S cm^2 mol^(-1) . Calculate the degree of dissociation of acetic acid. Given that lamda_(H^+)^(infty) and lambda_(CH_3COO^-)^(infty) are 349.8 and 40.9 ohm^(-1) cm^2 mol^(-1) respectively.

0.0024 (M) Acetic acid solution has specific conductance 7.896xx10^-5 S cm^-1 . What is the molar conductance of ACOH and also find degree of dissociation of it?