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Calculate the degree of dissociation (al...

Calculate the degree of dissociation `(alpha)` of acetic acid it its molar conductivity `(Lambda_(m))` is `"39.05 S.cm"^(2)."mol"^(-1)` Given `lambda_(H)^(@)="349.6 S.cm"^(2)."mol"^(-1)` and `lambda_(CH_(3)COO^(-))^(@)="40.9 S.cm"^(2)."mol"^(-1)`.

Text Solution

Verified by Experts

`Lambda_(CH_(3)COOH)=lambda_(H^(+))^(@)+lambda_(CH_(3)COO^(-))^(@)`
`=349.6+40.9="390.5 S.cm"^(2)."mol"^(-1)`
`alpha=(Lambda_(m))/(Lambda_(m)^(@))=(39.05)/(390.5)=0.1=10%`
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