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Given : K^(+)|K=-2.79V, Ag^(+)|Ag=0.80V,...

Given : `K^(+)|K=-2.79V, Ag^(+)|Ag=0.80V,`
`Hg^(2+)|Hg=0.79V, Mg^(2+)|Mg=-2.37V` and `Cr^(3+)|Cr=-0.74V`. Arrange these metals in their increasing order of reducing power.

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The smaller the electrode potential of metal, the greater is its reducing power. Thus the order of increasing reducing power of the metals is : `Ag lt Hg lt Cr lt Mg lt K`.
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CHHAYA PUBLICATION-ELECTROCHEMISTRY-SOLVED NCERT TEXTBOOK PROBLEMS (NCERT EXERCISE QUESTIONS)
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