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The conductivity of 0.20 M solution of K...

The conductivity of 0.20 M solution of KCl at 298 K is `0.0248 S.cm^(-1)`. Calculate the molar conductivity of the KCl solution.

Text Solution

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Given, conductivity, `k=0.0248 S.cm^(-1)`
and molarity, `C=0.2 M = 0.2 mol.L^(-1)`
`therefore` Molar conductivity, `Lambda_(m)=(k xx1000)/(C )=(0.0248xx1000)/(0.2)`
`=124S.cm^(2).mol^(-1)`
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