The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is `1500 Omega`. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K is `0.146xx10^(-3)S.cm^(-1)`.

Explanation

`C=0.001M, R = 1500 Omega, k = 0.146xx10^(-3)S.cm^(-1)`.
`therefore` Cell constant `=("Conductivity")/("Conductance")`
= Conductivity `xx` Resistance
`=(0.146xx10^(-3))xx1500=0.219cm^(-1)`