A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH = 10 and by passing hydrogen gas around the platinum wire at 1 atm pressure. The oxidation potential of electrode would be -

Options

A. 1.18V
B. 0.059V
C. 0.59V
D. 0.118V

Answer

C

Explanation

`H_(2)" (1 atm)"rarr 2H^(+)+2e`
`E=E^(@)-(0.059)/(2)log.([H^(+)]^(2))/(p_(H_(2)))`
`=0-(0.059)/(2)log.((10^(-10))^(2))/(1)=+0.59V`