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Use the given data - E(Cr(2)O(7)^(2-)...

Use the given data -
`E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=+1.33V, E_(Cl_(2)|Cl^(-))^(@)=+1.36V`
`E_(MnO_(4)^(-)|Mn^(2+))^(@)=+1.51V, E_(Cr^(3+)|Cr)^(@)=-0.74V`and find out the most stable oxidised species -

A

`Cr^(3+)`

B

`MnO_(4)^(2-)`

C

`Cr_(2)O_(7)^(2-)`

D

`Mn^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
A
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Use the given data - E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=+1.33V, E_(Cl_(2)|Cl^(-))^(@)=+1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=+1.51V, E_(Cr^(3+)|Cr)^(@)=-0.74V and find out the most stable ion in its reduced form -

Use the given data E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=+1.33V, E_(Cl_(2)|Cl^(-))^(@)=+1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=+1.51V, E_(Cr^(3+)|Cr)^(@)=-0.74V find out in which option the order of reducing power is correct -

Using the data find out the strongest reducing agent - E_(Cr_(2)O_(7)^(2-)|Cr^(+))^(@)=+1.33V, E_(Cl_(2)|Cl^(-))^(@)=+1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=+1.51V, E_(Cr^(2+)|Cr)^(@)=-0.74V

Given : E_(Cr^(3+)|Cr)^(@)=-0.74V, E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V, E_(Cl|Cl^(-))^(@)=1.36V Based on the data, strongest oxidising agent -

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Given, E_(Cu^(2+)|Cu)^(@)=+0.34V, E_(Fe^(3+)|Fe)^(@)=-0.036V,E_(I_(2)|2I^(-))^(@)=+0.54V and E_(Br_(2)|2Br^(-))^(@)=+1.06V . Which of the following statement is incorrect -

Given that, E_(Zn^(2+)|Zn)^(@)=-0.76V, E_(Cu^(2+)|Cu)^(@)=+0.34V , E_(Ni^(2+)|Ni)^(@)=-0.25V and E_(Ag^(+)|Ag)^(@)=+0.80V Which metal ions will be oxidised by Ag^(+) ion?

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