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If the equivalent ionic conductances of `Al^(3+) and SO_(4)^(2-)` ions are `lambda_(Al^(3+))^(@) and lambda_(SO_(4)^(2-))^(@)`, respectively, in an infinitely dilute solution of `Al_(2)(SO_(4))_(3)`, then the equivalent conductance of the solution would be -

A

`2lambda_(Al^(3+))^(@)+3lambda_(SO_(4)^(2-))^(@)`

B

`lambda_(Al^(3+))^(@)+lambda_(SO_(4)^(2-))^(@)`

C

`6(lambda_(Al^(3+))^(@)+lambda_(SO_(4)^(2-))^(@))`

D

`(1)/(3)lambda_(Al^(3+))^(@)+(1)/(2)lambda_(SO_(4)^(2-))^(@)`

Text Solution

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The correct Answer is:
B
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