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For the cell, Cu|Cu^(2+)||Hg^(2+)|Hg, E(...

For the cell, `Cu|Cu^(2+)||Hg^(2+)|Hg, E_("cell")^(@)=+0.45V`. Find the standard reduction potential of `Hg^(2+)|Hg` electrode. Given : `E_(Cu^(2+)|Cu)^(@)=+0.34V.`

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`E_("cell")^(@)=E_(Hg_(2)^(2+)||Hg)^(0)-E_(Cu^(2+)||Cu)^(@)`
or, `0.45V=E_(Hg_(2)^(2+)||Hg)^(@)-0.34V`
`therefore E_(Hg_(2)^(2+)||Hg)^(@)=+0.79V`
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