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A Zn - electrode is dipped in a 0.1 (M) ...

A Zn - electrode is dipped in a 0.1 (M) `ZnSO_(4)` solution. The salt in `95%` dissociated in solution. Find the reduction potential of the electrode. Given : Temperature `=298K, E_(Zn^(2+)|Zn)^(@)=-0.76V`

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`E_(Zn^(2+)||Zn)^(@)=E_(Zn^(2+)||Zn)^(@)+(0.059)/(2)log[Zn^(2+)],`
`E_(Zn^(2+)||Zn)^(@)=-0.79V`
`and [Zn^(2+)]=-.1xx0.95=0.095(M)`
`therefore" "E_(Zn^(2+)||Zn)=-0.79V`
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