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The EMF of the galvanic cell, Zn|Zn^(2+)...

The EMF of the galvanic cell, `Zn|Zn^(2+)(2.0M)||Cu^+(xM)Cu` is 0.86V. If `E_(Zn^(2+)|Zn)^(@)=-0.76V` and `E_(Cu^(+)|Cu)^(@)=+0.15V`, then find the value of x.

Text Solution

Verified by Experts

`Zn+2Cu^(+)rarrZn^(2+)+2Cu, E=E^(@)-(0.059)/(2)log.([Zn^(2+)])/([Cu^(2+)])`
or, `0.87=0.91-(0.059)/(2)log.(2)/([Cu^(2+)]^(2))`
`therefore" "[Cu^(2+)]=0.29(M)`
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