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Given : Cu^(2+)+2e rarrCu, E^(@)=+0.34V ...

Given : `Cu^(2+)+2e rarrCu, E^(@)=+0.34V and AG^(+)+e rarr Ag, E^(@)=+0.80V`. (i) Construct a galvanic cell with these two electrodes. (ii) If at `25^(@)C` the concentration of `Cu^(2+)` is 0.01 (M), what should be the value of concentration of `Ag^(+)` to make the cell potential equal to zero?

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`Cu+2Ag^(+)rarr Cu^(2+)+2Ag,E=E^(@)-(0.059)/(2)log.([Cu^(2+)])/([Ag^(+)]^(2))`
or, `0=0.46-(0.059)/(2)log.(0.01)/([Ag^(+)]^(2))`
`therefore" "[Ag^(+)]=1.59xx10^(-9)(M)`
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