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Calculate cell potential of Fe|Fe^(2+)...

Calculate cell potential of
`Fe|Fe^(2+)(a=0.6)||Sn^(2+)(a=0.2)|Sn`
Given : `E_(Fe^(2+)|Fe)^(@)=-0.44V, E_(Sn^(2+)|Sn)^(@)=+0.14V`

Text Solution

Verified by Experts

`E_("cell")=E_("cell")^(@)-(0.059)/(2)log.([Fe^(2+)])/([Sn^(2+)])`
`=(0.14+0.44)-(0.059)/(2)log.(0.6)/(0.2)=0.566V`
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