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The cell constant of a conductivity cell...

The cell constant of a conductivity cell is `"0.228 cm"^(-1)`. If the cell is filled with `"0.005 (N) K_(2)SO_(4)` solution, the resistance recorded is 326 ohm at `25^(@)C`. What will be (i) the specific conductance and (ii) the equivalent conductivity of the solution?

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`kappa=(l)/(A)xx(l)/(R)=0.228xx(1)/(326)=6.994xx10^(-4)" ohm"^(-1)."cm"^(-1)`
`Lambda = kappa xx(1000)/(N)=6.994xx10^(-4)xx(1000)/(0.005)`
`="139.88 ohm"^(-1)."cm"^(2)."g- equiv"^(-1)`
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