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Equivalent conductivities at infinite di...

Equivalent conductivities at infinite dilution `(Lambda^(@))` of `NH_(4)Cl, NaOH` and `NaCl` are 130, 217.6 and `"108.9 ohm"^(-1)."cm"^(2).g-equiv"^(-1)` respectively at `25^(@)C`. Calculate `Lambda^(@)` of `NH_(4)OH` at `25^(@)C`

Text Solution

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`Lambda_(NH_(4)OH)^(@)=Lambda_(NH_(4)Cl)^(@)+Lambda_(NaOH)^(@)-Lambda_(NaCl)^(@)`
`=(130+217.6-108.9)="238.7 ohm"^(-1)."cm"^(2)."g-equiv"^(-1)`
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