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Calculate the weight of water decomposed...

Calculate the weight of water decomposed, if 5 ampere current is passed through acidified water for 5 h?

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`A=Ixxt=5xx5xx3600=9xx10^(4)C.`
`H_(2)O(l)rarrH_(2)(g)+(1)/(2)O_(2)(g)" "[2H^(+)+2erarrH_(2)]`
`2xx96500C-="1 mol "H_(2)" "therefore" "9xx10^(4)C-="0.4663 mol "H_(2)`
But, 1 mol `H_(2)` is obtained from 18 g water.
So, 0.4663 mol `H_(2)` comes from `1.8xx0.4663=8.3934g` water.
`therefore 9xx10^(4)C` decomposes 8.3934 g water.
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