3.7 A current was passed for 6h through 0.5L 2( M ) solution of `Ni(NO_(3))_(2)` . What will be the molarity of the solution after electrolysis ?

Explanation

`Q=Ixxt=3.7xx6xx3600=79920C`
`"0.5 L 2(M) of "Ni(NO_(3))_(2)-="1 mol "Ni^(2+)` ion
`Ni^(2+)+2e rarr Ni`
`therefore" "2xx96500C-=" reduction of 1 mol "Ni^(2+)" ions So, "79500C-=" reduction of 0.414 mol "Ni^(2+)" ions Strength of the solution after electrolysis"`
`=(1-0.414)/(0.5)=1.172(M)`