27g Al is discharged , when 0.5 A current is passed through molten `AlCl^(3)` . Calculate ( 1 ) the number of gram equivalents of Al discharged ( ii ) the number of gram atoms of Al discharged ( iii ) the number of molecules of Al discharged ( iv ) the number of electrons that took part in the process ( v ) the amount of electricity ( in F ) that was used ( vi ) the duration of passage of electricity ( vil ) the volume of `Cl_(2)` , ( in L ) produced at STP .

Explanation

`Al^(3+)+3erarrAl` (i) number of gram - equivalent of aluminium liberated `=(27)/(9)=3`, (ii) `(27)/(27)=1` gram - atom, (iii) `6.023xx10^(23)`, (iv) `3xx6.023xx10^(23)`, (v) 3F,
(iv) `3xx96500=0.5xxt," "therefore t=5.79xx10^(5)s`
(vii) `Cl rarr(1)/(2)Cl_(2)+e," 1 F "-=11.2LCl_(2)" (at NTP)`
`therefore 3F=33.6LCl_(2)" (at NTP)"`