`MnO_(2)` , is prepared by electrolysis of an aqueous solution of mnso4 acidified with `H_(2)SO_(4)` . The reaction is `Mn^(2+)(aq)+2H_(2)OrarrMnO_(2)(s)+2H^(+)(aq)+H^(2)(g)` . 1kg of `MnO_(2)` , is produced , when 27A current is passed for 24 h . What is the efficiency of the current passed ? Write the cathode and anode reactions .

Explanation

`Q=Ixxt=27xx24xx3600=2.3328xx10^(6)C`
`Mn^(2+)+2H_(2)Orarr MnO_(2)+4H^(+)+2e`
Hence, `86.9 g MnO_(2)-=2xx96500C`
`therefore" Hence, 86.9 g "MhO_(2)-=2xx96500C`
`therefore" 100 g MnO"_(2)-=2.22xx10^(6)C`
`therefore" Current efficiency "=(2.22xx10^(6))/(2.3328xx10^(6))=95.16%`