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500 mL 4 M of NaCl solution is electroly...

500 mL 4 M of NaCl solution is electrolysed liberating `Cl_(2)(g)` at an electrode. Calculate (1) the total number of moles of `Cl_(2)`

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`"500 mL 4 M NaCl"-="2 mol Cl"^(-)" and 2 mol Na"^(+)`
`Cl^(-)(aq)rarr (1)/(2)Cl_(2)(g)+e`
From the above reaction, it is said that `(1)/(2)` mole `Cl_(2)(g)` is obtained from 1 mole `Cl^(-)` ion.
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