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500 mL 4 M of NaCl solution is electroly...

500 mL 4 M of NaCl solution is electrolysed liberating `Cl_(2)(g)` at an electrode. Calculate (2) the maximum amount of amalgam if Hg - cathode is used (atomic mass of Hg = 200 )

Text Solution

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`Na^(+)+e rarr Na`
`therefore" 2 mol "Na^(+)-="2 mol Na metal"-="46 g Na"`
`therefore" Maximum amount of amalgam"`
`=2xx200+46=446g`.
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