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Following data were obtained during firs...

Following data were obtained during first order thermal decomposition of -
`SO_(2)Cl_(2)(g)rarrSO_(2)(g)+Cl_(2)(g)`
`{:("Experiment","time"(s^(-1)),"Total pressure"("atm")),(1,0,0.4),(2,100,0.7):}`
Calculate the rate constant . (Given : log4 = 0.6021, log2 = 0.3010)

Text Solution

Verified by Experts

Thermal decomposition of `SO_(2)Cl_(2)` at constant volume is :
`" "SO_(2)Cl(g) rarrSO_(2)(g)+Cl_(2)(g)`
`{:("Initial pressure:",p_(0),0,0),("After time t",p_(0)-p,p,p):}`
Total pressure after time t: `P_(t)=(P_(0)-p)+p+p=P_(0)+p`
`therefore p=P_(t)-P_(0)." If "apropP_(0),(a-x)propP_(0)-p`
Substituting for p , we get `a-xpropP_(0)-(P_(t)-P_(0))`
or, `(a-x)prop2P_(0)-P_(t)`
Rate constant, `k=(2.303)/(t)log.([A]_(0))/([A])=(2.303)/(t)log.(P_(0))/(2P_(0)-P_(t))`
When `t=100s,k=(2.303)/(100)log.(0.4)/(2xx0.4-0.7)=0.0139s^(-1)`
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