Home
Class 12
CHEMISTRY
The decomposition of hydrocarbon follows...

The decomposition of hydrocarbon follows the equation k ` =(4.5xx10^(11)s^(-1))e^(-28000K//T)` . Calculate `E_(a)`.

Text Solution

Verified by Experts

According to Arrhenius equation , `k=Ae^(-E_(a)//Rt)`
Given, `k = (4.5xx10^(11))e^(-28000K//T)`
Comparing with the Arrhenius equation,
`therefore-(E_(a))/(RT)=(-28000K)/(T) " or, "E_(a)=(28000)/(T)xxRT=28000R`
`thereforeE_(a)=28000xx8.314=232.79"kJ.mol"^(-1)`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|18 Videos

  • CHEMICAL KINETICS

    CHHAYA PUBLICATION|Exercise ADVANCED LEVEL NUMERICAL BANK|16 Videos

  • CHEMICAL KINETICS

    CHHAYA PUBLICATION|Exercise SOLVED NCERT TEXTBOOK PROBLEMS (NCERT INTEXT QUESTIONS)|21 Videos

  • BIOMOLECULES

    CHHAYA PUBLICATION|Exercise Practic Set 29|1 Videos

  • CHEMICAL THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise Practice Set 6|15 Videos

Similar Questions

Explore conceptually related problems

The decomposition of a hydrocarbon follows the equation k= (4.5 xx 10^11s^-1)e^-28000K/T. Activation energy of the reaction is

The rate constant for the first order decomposition of H_(2)O_(2) is given by the following equation: logk=14.34-1.25xx10^(4)K//T Calculate E_(a) for this reaction and rate constant k if its half-life period is 256 minutes.

The rate constant for the first order decomposition of H_(2)O_(2) is given by the following equation: logk=14.2-(1.0xx10^(4))/(T)K Calculate E_(a) for this reaction and rate constant k if its half-life period is 200 minutes.

The rate constant for the first order decomposition of H_2O_2 is given by the following by the equation log k= 14.34 - 1.25 xx 10^4 K/T Calculate E-a for this reaction and at what temperature will its half-period be 256 minutes /.

The decomposition of N_2O into N_2 and O_2 follows second order kinetics with k = (5.0 xx 10^(11) L "mol"^(-1) s^(-1)) e^(-(41570)/(T))" , it suggests that

The rate constant of a first order reaction follows the equation logk(s^(-1))=22.3-(12.16xx10^(3))/(T)K Find the activation energy of the reaction.

The decomposition of A into product has value of k as 4.5xx10^(3)s^(-1) " at" 10^(@)C and energy of activation 60"kJ.mol"^(-1) . At what temperature would k be 1.5xx10^(4)s^(-1) ?

The rate constant of a first order reaction follows the equation logk(s^(-1))=22.3-(12.16xx10^(3))/(T)K At what temperature will the half-life of the reaction be 115.5 min ?

The rate constant for the decomposition of hydrocarbons is 2.418xx10^(-5)s^(-1) as 546 K . If the energy of activation is 179.9 kJ.mol , what will be the value of pre-exponential factor ?

CHHAYA PUBLICATION-CHEMICAL KINETICS-SOLVED NCERT TEXTBOOK PROBLEMS (NCERT EXERCISE QUESTIONS)
  1. The experimental data for decomposition of N(2)O(2) [2N(2)O(5)rarr4NO(...

    Text Solution

    |

  2. The experimental data for decomposition of N(2)O(2) [2N(2)O(5)rarr4NO(...

    Text Solution

    |

  3. The experimental data for decomposition of N(2)O(2) [2N(2)O(5)rarr4NO(...

    Text Solution

    |

  4. The experimental data for decomposition of N(2)O(2) [2N(2)O(5)rarr4NO(...

    Text Solution

    |

  5. The experimental data for decomposition of N(2)O(2) [2N(2)O(5)rarr4NO(...

    Text Solution

    |

  6. The rate constant for a first order reaction is 60s^(-1) How much time...

    Text Solution

    |

  7. During nuclear explosion, one of the products is .^(90)"Sr" with half...

    Text Solution

    |

  8. For a first order reaction , show that time required for 99% completio...

    Text Solution

    |

  9. A first order reaction takes 40 min for 30% decomposition . Calculate ...

    Text Solution

    |

  10. For the decomposition of azoisopropane to hexane and nitrogen at 543 K...

    Text Solution

    |

  11. The following data were obtained during the first thermal decompositio...

    Text Solution

    |

  12. The rate constant for the decomposition of N(2)O(5) at various tempera...

    Text Solution

    |

  13. The rate constant for the decomposition of hydrocarbons is 2.418xx10^(...

    Text Solution

    |

  14. Consider a certain reaction Ararr products with k=2.0xx10^(-2)s^(-1) ...

    Text Solution

    |

  15. Sucrose decomposes in acid solution into glucose and fructose accordin...

    Text Solution

    |

  16. The decomposition of hydrocarbon follows the equation k =(4.5xx10^(1...

    Text Solution

    |

  17. The rate constant for the first order decomposition of H(2)O(2) is gi...

    Text Solution

    |

  18. The decomposition of A into product has value of k as 4.5xx10^(3)s^(-...

    Text Solution

    |

  19. The time required for 10% completion of a first order reaction at 298K...

    Text Solution

    |

  20. The rate of a reaction quadruples when the temperature changes from 2...

    Text Solution

    |