`SO_(2)` possess both oxidising and reducing property, while `SO_(3)` possess only oxidising property. Explain.

Explanation

In `SO_(2)` the oxidation states is + 4. The higest and lowest oxidation states of S are +6 are -2 repectivly. Hence , S - atom in `SO_(2)` is present in an intermediate oxidation state. So , it can enhance its oxidation state by reducing other elemebts/ compounds. Again it can decrease its oxidation state by oxidation other elemens/compound. Thus `SO_(2)` exhibts both oxidising and reducing properties.
In `SO_(3)` S - atoms is present in its maxium oxidation state (+6). Hence `SO_(3)` has not potential to get oxidised, i.e., it has no reducing property. But `SO_(3)` has oxiding state property because S -atom in `SO_(3)` can reduce its oxidiation state.