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Why is K(a(2))ltltK(a(1)) for H(2)SO(4) ...

Why is `K_(a_(2))ltltK_(a_(1))` for `H_(2)SO_(4)` in water?

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Verified by Experts

`H_(2)SO_(4)` is a dibasic acid. It undergoes ionisation in two stages. Hence, it has two different dissociation constants.
1. `H_(2)SO_(4)+H_(2)OtoH_(3)O^(+)+HSO_(4)^(-),K_(a_(1))gt10`
2. `HSO_(4)^(-)+H_(2)OtoH_(3)O^(+)+SO_(4)^(2-),K_(a_(2))=1.2xx10^(-2)`
Since the tendency of `HSO_(4)^(-)` ion to donate a proton to `H_(2)O` is less than that of neutral `H_(2)SO_(4)`, so `K_(a_(2))ltK_(a_(1))`
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