Home
Class 12
CHEMISTRY
Calculate the value of 'spin only' magne...

Calculate the value of 'spin only' magnetic moment of `M^(2+)(aq)` atomic number of M = 27.

Text Solution

Verified by Experts

Number of unpaired electrons for atomic no 27, n = 3
`mu_("so")=sqrt(n xx(n+2))=sqrt(3 xx(3+2))=3.87 M`.
Promotional Banner

Topper's Solved these Questions

  • D - AND F - BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise QUESTION - ANSWER ZONE FOR BOARD EXAMINATION (VERY SHORT ANSWER TYPE)|38 Videos

  • D - AND F - BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise QUESTION - ANSWER ZONE FOR BOARD EXAMINATION (SHORT ANSWER TYPE)|41 Videos

  • COORDINATION COMPOUNDS OR COMPLEX COMPOUNDS

    CHHAYA PUBLICATION|Exercise PRACTICE SET 21|2 Videos

  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise PRACTICE SET 4(Answer the following questions)|14 Videos

Similar Questions

Explore conceptually related problems

Calculate the 'spin only' magnetic moment of M^(2+)(aq)[Z=27] ion.

Calculate spin only magnetic moment of Cu^(2+) .

Calculate the spin only magnetic moment of Fe^(2+) ion.

Calculate spin only magnetic moment of Ni^(2+) ion.

The spin -only magnetic moment of [CrF_6]^(4-) (atomic number of Cr is 24) is

Calculate spin only magnetic moment of Fe^(3+) ion.