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Write the number of unpaired electron(s)...

Write the number of unpaired electron(s) present in `Na_(2)[FeO_(4)]`. [Atomic number of Fe is 26]

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Let, in sodium ferrate `Na_(2)[FeO_(4)]`, the oxidation state of `Fe = x therefore 2xx1+x+4xx(-2)=0`.
In + 6 state, the outer electronic configuration of Fe is `3d^(2)4s^(0)`.
So, number of unpaired electrons of iron in the given compound = 2.
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