Which is a stronger reducing agent `Cr^(2+)` or `Fe^(2+)` & Why ?

Explanation

`E_(Cr^(3+)|Cr^(2+))^(0)=-0.41V, E_(Fe^(3+)|Fe^(2+))^(0)=+0.77V`
The reducing agent of the system having lower standard reduction potential value will reduce the oxidising agent of the other system, having higher standard reduction potential value. Therefore, `Cr^(2+)` is stronger reducing agent then `Fe^(2+)`.