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In acidic medium, H(2)O(2) changes Cr(2)...

In acidic medium, `H_(2)O_(2)` changes `Cr_(2)O_(7)^(2-)` to `CrO_(5)` which has two `(-O-O-)` bonds. Oxidation state of Cr in `CrO_(5)` is -

A

`+5`

B

`+3`

C

`+6`

D

`-10`

Text Solution

Verified by Experts

The correct Answer is:
C

`x + [1xx(-2)]+[4xx(-1)]=0`
(for Cr)(for O) (for O-O)
or, `x-2-4=0` or, `x=+6`
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