Match the metal ions given in column - I with the spin magnetic moments of the ions given in coloumn - II and assign the correct code -
`{:(,"Column - I",,"Column - II"),((a),Co^(3+),(i),sqrt(8)BM),((b),Cr^(3+),(ii),sqrt(35)BM),((c ),Fe^(3+),(iii),sqrt(3)BM),((d),Ni^(2+),(iv),sqrt(24)BM),(,,(v),sqrt(15)BM):}`

Options

A. (a)-(iii), (b)-(v), (c )-(i), (d)-(ii)
B. (a)-(iv), (b)-(v), (c )-(ii), (d)-(i)
C. (a)-(iv), (b)-(i), (c )-(ii), (d)-(iii)
D. (a)-(i), (b)-(ii), (c )-(iii), (d)-(iv)

Answer

B

Explanation

`Co^(3+) : [Ar]3d^(6)`, unpaired electron (n) = 4
`therefore` Spin magnetic moment `= sqrt(4(4+2))=sqrt(24)BM`
`Cr^(3+):[Ar]3d^(3)`, unpaired electron (n) = 3
`therefore` Spin magnetic moment `= sqrt(3(3+2))=sqrt(15)BM`
`Fe^(3+):[Ar]3d^(5)`, unpaired electron (n) = 5
`therefore` Spin magnetic moment `= sqrt(5(5+2))=sqrt(35)BM`
`Ni^(2+):[Ar]3d^(8)`, unpaired electron (n) = 2
`therefore` Spin magnetic moment `= sqrt(2(2+2))=sqrt(8)BM`