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Magnetic moment of Cr^(2+) is nearest to...

Magnetic moment of `Cr^(2+)` is nearest to -

A

`Fe^(2+)`

B

`Mn^(2+)`

C

`Co^(2+)`

D

`Ni^(2+)`

Text Solution

Verified by Experts

The correct Answer is:
A

`Cr^(2+)=3d^(4)`, number of unpaired electrons (n) = 4
Magnetic moment `= sqrt(n(n+2))BM=sqrt(4(4+2))=sqrt(24)BM`
`Fe^(2+)=3d^(6)`, number of unpaired electrons (n) = 4
Magnetic moment `= sqrt(4(4+2))BM=sqrt(24)BM`
`Mn^(2+)=3d^(5)`, number of unpaired electrons (n) = 5
Magnetic moment `= sqrt(5(5+2))BM = sqrt(35)BM`
`Co^(2+)=3d^(7)` , number of unpaired electrons (n) = 3
Magnetic moment `= sqrt(3(3+2))BM = sqrt(15)BM`
`Ni^(2+)=3d^(8)`, number of unpaired electrons (n) = 2
Magnetic moment `= sqrt(2(2+2))BM = sqrt(8)BM`
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