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Least number of oxidation states is show...

Least number of oxidation states is shown by -

A

Np (Neptunium)

B

Th (Thorium)

C

U (Uranium)

D

Re (Rhenium)

Text Solution

Verified by Experts

The correct Answer is:
B
`Np(+3,+4,+5,+6), Th (+3, +4)`,
`U(+3,+4,+5,+6)` and `Re(2+,+4,+6,+7,-1)`
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