Write the isomers of the compound having formula `C_(4)H_(9)Br`.

Explanation

D.B.E. For `C_(4)H_(9)Br = (4+1)-(9+1)/(2) = 0`
Thus it is a saturatedacyclic compound, i.e., an alkyl halide. The possible isomers are -
`underset(1-"bromobutane")(overset(4)(C)H_(3)overset(3)(C)H_(2)overset(2)(C)H_(2)overset(1)(C)H_(2)Br)` (ii) `underset(2-"bromobutane")(overset(4)(C)H_(3)-overset(3)(C)H_(2)-underset(Br)underset(|)(overset(2)(C)H-overset(1)(C)H_(3)))`
(iii) `underset(1-"bromo"-2-"methylpropane")(overset(3)(C)H_(3)-underset(CH_(3))underset(|)overset(2)(C)H-overset(1)CH_(2)B)f` (iv) (ii) `underset(2-"bromo"-2-"methylpropane")(overset(1)(C)H_(3)-underset(Br)underset(|)overset(CH_(3))overset(|)(.^(2)C)-overset(3)CH_(3))`.