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Which compound in each of the following ...

Which compound in each of the following pairs will react faster in `S_(N)2` reaction with `OH^(-)`?
1. `CH_(3)Br or CH_(3)I`.

Text Solution

Verified by Experts

`I^(Theta)` is a better leaving group than `Br^(Theta)`. So `CH_(3)I` reacts faster with `OH^(Theta)` ion in the `S_(N)2` pathway.
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Which halogen compound in each of the following pairs will reacts faster in S_(N)2 reaction: CH_(3)Br or CH_(3)I .

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Which of the compounds will react faster in S_(N)1 reaction with the OH^(-) ion? CH_(3)-CH_(2)-Cl or C_(6)H_(5)-CH_(2)-Cl .

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CH_(3)Cl is unreactive towards S_(N)1 reaction - why?

Which one of each pair will not undergo S_(N)2 reaction and why? (i) (CH_3)_(3)C CH_(2)Cl, CH_(3)CH_(2)Cl .

Arrange the following in the order of increasing S_(N)2 reactivity and explain the order : CH_(3)F, CH_(3)I, CH_(3) Br, CH_(3)Cl .

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