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In a conductive cell, at 298K, the resis...

In a conductive cell, at 298K, the resistance of 0.05M NaOH solution is 31.16. Ifthe cell constant of that cell is 0.367`cm^(-1) , then calculate molar conductance of the given solution.

Text Solution

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Molar conductance, `^^_m=kxx(1000)/M`
Specific conductance, `k=Lxxl/A=1/Rxx1/A`
`=1/(31.16)xx0.367Omega^(1)*cm^(-1)`
`=0.118Omega^(-1)*cm^(-1)`
`:." "^^_m=0.0118xx(1000)/(0.05)=236Omega^(-1)*cm^2*mol^(-1)`
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