Two constat forece `vecF_(1) = (2hati + 3hatj + 3hatk)` newton and `vecF_(2) = (5hati - 6hatj - 2hatk)` newton act toghter on a particle during its displacement from the position `(20hati + 15hatj)`m to `8vecKm`. Calculate the work done.

Answer

`-87` joule

Explanation

`vecF_(1) = 2hati + 3hatj + 3hatk`
`vecF_(2)= 5hati - 6hatj + hatk`
`vecF_("net") = 7 hati - 3hatj + hatk`
`vecr_(1) = 20hati + 15hatj" "vecr_(2) = 8hatk`
Work done ` = (vecF_("net") ).(vecr_("net"))= - 87 "joule"`