Compute the force (in vetcor notation ) on an electron moving with velocity `vecV = 2.5 xx 10^(6)hati m//s` in a magnetic field `vecB =(10hati- 6 hatk) xx 10 ^(2) Wb//m^(2)`, if charge on an electron `e =1.6 xx 10^(-19)` coulomb.

Answer

`vecF= 2.4 xx 10^(-10)hatj` newton

Explanation

`vecF= q (vecv xx vecB)`
`=q[(2.5 xx 10^(6))hati xx (10 xx 10^(2)) hati- (6 xx 10^(2))hatk]N`
`= 1.6xx 10 ^(-19) xx 15xx 10^(8) hatj N`
`= 2.4 xx 10^(-10)hatjN`