The particle of mass m is projected at `t=0` from a point O on the ground with speed `v_(0)` at an angle `45^(@)` to the horizontal as shown in Figure 3.44. Compute the magnitude and direction of the angular mometum of the particle about the point O at position :

When the velocity of the paticle is , `vecV= (0,7v_(0))hati-(0.3v_(0))hatj`

Answer

Magnitude = `0.35 mv_(0)^(3)//g` and direction along negtive z- axis