A particle moves such that `x = 2t^(3) + t+ 8, y=t^(2) + t+ 3` and `z=3 sin pit` where x, y, z are in meter and t in seconds.
Calculate the acceleration of the particle at ` t = 3` second.

Answer

`(36 hati + 2hatj) m//s ^(2)`

Explanation

`x = 2t^(3) + t+ 8" "…..(ii)`
`y= t^(3) + t+3" ".....(ii)`
`z = 3sin pit" ".....(iii)`
`(d^(2)x)/(dt^(2))= 12 t hati`
`(d^(2) y)/(dt^(2)) = 2hatj`
`t=3 sec`
`n = 36`
`y = 2`
`36 hati + 2 hatj`