Home
Class 11
PHYSICS
The momentum of a particle is given by ...

The momentum of a particle is given by `vecP= (2 sin t hati- 2cos t hatj)kgm//s`. Select the correct option:

A

Momentum `vecp` of the particle is always perpendicular to `vecF`

B

Momentum `vecp` of the particle is always parallel t `vecF`

C

Magnitude of momentum remains constant

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
A, C

`vecp =2 sin t hati - 2 cos t hatj`
`vecF = (d vecp)/(dt)= 2 cos t hati + 2 sin that j`
`therefore" "vecF. vecp = 0 rArr vecF botvecp `
Also, `|vecp|= sqrt((2sin t)^(2)+ (2 cos t)^(2) )= 2=` constant.
Promotional Banner

Topper's Solved these Questions

  • VECTORS

    GRB PUBLICATION|Exercise ASSERTION- REASON|1 Videos
  • VECTORS

    GRB PUBLICATION|Exercise MATRIX- MATCH|4 Videos
  • VECTORS

    GRB PUBLICATION|Exercise OBJECTIVE QUESTIONS|120 Videos
  • UNITS AND DIMENSIONS

    GRB PUBLICATION|Exercise Link Compression|6 Videos

Similar Questions

Explore conceptually related problems

The linear momentum of a particle is given by vec(P)=(a sin t hati- acos t hatj) kg- m//s . A force vec(F) is acting on the particle. Select correct alternative/s:

The position vector of a particle is given by vecr=(2 sin 2t)hati+(3+ cos 2t)hatj+(8t)hatk . Determine its velocity and acceleration at t=pi//3 .

The position of a particle is given by vecr = 2t^(2) hati + 3t hatj + 4hatk where t is in second and the coefficients have proper units for vecr to be in metre. The veca(t) of the particle at t = 1 s is

The momentum of a body is vec P =2 cos t hati +2 sin t hatj. What is the angle between the force vec F acting on the body and the momentum vec P ?

The position of a particle is given by vec r =(8 t hati +3t^(2) hatj +5 hatk) m where t is measured in second and vec r in meter. Calculate, direction of the velocity at t = 1 s

The momentum of a moving particle is vectorially given a, vecp=p_(0)(costhati+sinthatj) where t stands for time. Choose the correct option:

The position of a particle is given by vecr = 3t hati + 2t^(2) hatj + 5hatk , where t is in seconds and the coefficients have the proper units for vecr to be in metres. The direction of velocity of the particle at t = 1 s is

Position vector of a particle moving in space is given by : vec(r)=3sin t hat i+3 cos t hatj+4 t hatk Distance travelled by the particle in 2s is :

The position of a particle is given by r = 3t hati +2t^(2) hatj +8 hatk where, t is in seconds and the coefficients have the proper units for r to be in meters. (i) Find v (t) and a(t) of the particles. (ii) Find the magnitude and direction of v(t) and a(t) at t = 1s .

The position of a particle is given by vecr = 3.01t hati +2. 0 t^2 hatj +5.0 hatk where t is in seconds and the coefficients have the proper units for vecr to be in metres. What is the magnitude and direction of velocity of the particle at t = 1 s? .